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snowflake.snowpark.functions.parse_json¶

snowflake.snowpark.functions.parse_json(e: ColumnOrName) → Column[source]¶

Parse the value of the specified column as a JSON string and returns the resulting JSON document.

Example:

>>> df = session.create_dataframe([['{"key": "1"}']], schema=["a"])
>>> df.select(parse_json(df["a"]).alias("result")).show()
----------------
|"RESULT"      |
----------------
|{             |
|  "key": "1"  |
|}             |
----------------

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