modin.pandas.DataFrameGroupBy.rank¶
- DataFrameGroupBy.rank(method='average', ascending=True, na_option='keep', pct=False, axis=_NoDefault.no_default)[source]¶
- Provide the rank of values within each group. - Parameters:
- method ({"average", "min", "max", "first", "dense"}) – How to rank the group of records that have the same value (i.e. break ties): - average: average rank of the group - min: lowest rank in the group - max: highest rank in the group - first: ranks assigned in order they appear in the array - dense: like ‘min’, but rank always increases by 1 between groups. 
- ascending (bool) – Whether the elements should be ranked in ascending order. 
- na_option ({"keep", "top", "bottom"}) – How to rank NaN values: - keep: assign NaN rank to NaN values - top: assign the lowest rank to NaN values - bottom: assign the highest rank to NaN values 
- pct (bool) – Whether to display the returned rankings in percentile form. 
- axis ({{0 or 'index', 1 or 'columns'}}, default None) – - The axis to use. 0 or ‘index’ for row-wise, 1 or ‘columns’ for column-wise. If axis is not provided, grouper’s axis is used. - Snowpark pandas does not currently support axis=1, since it is deprecated in pandas. - Deprecated: For axis=1, operate on the underlying object instead. Otherwise, the axis keyword is not necessary. 
 
- Return type:
- Seriesor- DataFramewith ranking of values within each group
 - Examples - >>> df = pd.DataFrame({"group": ["a", "a", "a", "b", "b", "b", "b"], "value": [2, 4, 2, 3, 5, 1, 2]}) >>> df group value 0 a 2 1 a 4 2 a 2 3 b 3 4 b 5 5 b 1 6 b 2 >>> df = df.groupby("group").rank(method='min') >>> df value 0 1 1 3 2 1 3 3 4 4 5 1 6 2