- Categories:
Semi-structured and structured data functions (Type Predicates)
IS_ARRAY¶
Returns TRUE if its VARIANT argument contains an ARRAY value.
- See also:
Syntax¶
IS_ARRAY( <variant_expr> )
Arguments¶
variant_expr
An expression that evaluates to a value of type VARIANT.
Usage notes¶
This function does not support a structured type as an input argument.
Examples¶
This shows how to use the function:
Create a table and data:
CREATE TABLE multiple_types ( array1 VARIANT, array2 VARIANT, boolean1 VARIANT, char1 VARIANT, varchar1 VARIANT, decimal1 VARIANT, double1 VARIANT, integer1 VARIANT, object1 VARIANT ); INSERT INTO multiple_types (array1, array2, boolean1, char1, varchar1, decimal1, double1, integer1, object1) SELECT TO_VARIANT(TO_ARRAY('Example')), TO_VARIANT(ARRAY_CONSTRUCT('Array-like', 'example')), TO_VARIANT(TRUE), TO_VARIANT('X'), TO_VARIANT('I am a real character'), TO_VARIANT(1.23::DECIMAL(6, 3)), TO_VARIANT(3.21::DOUBLE), TO_VARIANT(15), TO_VARIANT(TO_OBJECT(PARSE_JSON('{"Tree": "Pine"}'))) ;Now run the query:
SELECT IS_ARRAY(array1), IS_ARRAY(array2), IS_ARRAY(boolean1) FROM multiple_types; +------------------+------------------+--------------------+ | IS_ARRAY(ARRAY1) | IS_ARRAY(ARRAY2) | IS_ARRAY(BOOLEAN1) | |------------------+------------------+--------------------| | True | True | False | +------------------+------------------+--------------------+