Categories:

String & Binary Functions (Matching/Comparison)

LIKE ALL¶

Allows case-sensitive matching of strings based on comparison with one or more patterns.

The operation is similar to LIKE. If and only if the input string matches all of the patterns, this returns the input string.

See also:

LIKE

Syntax¶

<subject> LIKE ALL (<pattern1> [, <pattern2> ... ] ) [ ESCAPE <escape_char> ]
Copy

Arguments¶

Required:

subject

The string to compare to the pattern(s).

pattern#

The pattern(s) that the string is to be compared to. You must specify at least one pattern.

Optional:

escape_char

Character(s) inserted in front of a wildcard character to indicate that the wildcard should be interpreted as a regular character rather than as a wildcard.

Returns¶

The data type of the returned value is VARCHAR.

Usage Notes¶

  • SQL wildcards are supported in pattern:

    • An underscore (_) matches any single character.

    • A percent sign (%) matches any sequence of zero or more characters.

  • Wildcards in pattern include newline characters (\n) in subject as matches.

  • The pattern is considered a match if the pattern matches the entire input string (subject). To match a sequence anywhere within a string, start and end the pattern with % (e.g. %something%).

  • NULL does not match NULL. In other words, if the subject is NULL and one of the patterns is NULL, that is not considered a match.

  • If the function is used with a subquery, the subquery should return a single row.

    For example, the following should be used only if the subquery returns a single row:

    SELECT ...
    WHERE x LIKE ALL (SELECT ...)
    Copy

Examples¶

Create a table that contains some strings:

CREATE OR REPLACE TABLE like_all_example(subject varchar(20));
INSERT INTO like_all_example VALUES
    ('John  Dddoe'),
    ('Joe   Doe'),
    ('John_do%wn'),
    ('Joe down'),
    ('Tom   Doe'),
    ('Tim down'),
    (null);
Copy

This query shows how to use patterns with wildcards (%) to find matches:

SELECT * 
  FROM like_all_example 
  WHERE subject LIKE ALL ('%Jo%oe%','J%e')
  ORDER BY subject;
+-------------+
| SUBJECT     |
|-------------|
| Joe   Doe   |
| John  Dddoe |
+-------------+
Copy

This query shows how all patterns need to match for successful result:

SELECT * 
  FROM like_all_example 
  WHERE subject LIKE ALL ('%Jo%oe%','J%n')
  ORDER BY subject;
+---------+
| SUBJECT |
|---------|
+---------+
Copy

This query shows how to use an escape character to indicate that characters that are usually wild cards (_ and %) should be treated as literals.

SELECT * 
  FROM like_all_example 
  WHERE subject LIKE ALL ('%J%h%^_do%', 'J%^%wn') ESCAPE '^'
  ORDER BY subject;
+------------+
| SUBJECT    |
|------------|
| John_do%wn |
+------------+
Copy
Language: English