- Categories:
DATEDIFF¶
Calculates the difference between two date, time, or timestamp expressions based on the date or time part requested. The function returns the result of subtracting the second argument from the third argument.
You can also use the minus sign (-
) to calculate the difference between two dates by subtracting one date from
another.
To add units of time to a date, time, or timestamp (for example, add two days to a date) or subtract units of time from them, you can use the DATEADD, TIMEADD, or TIMESTAMPADD function.
- See also:
Syntax¶
For DATEDIFF:
DATEDIFF( <date_or_time_part>, <date_or_time_expr1>, <date_or_time_expr2> )
For minus sign:
<date_expr2> - <date_expr1>
Arguments¶
For DATEDIFF:
date_or_time_part
The unit of time. Must be one of the values listed in Supported date and time parts (for example,
month
). The value can be a string literal or can be unquoted (for example,'month'
ormonth
).date_or_time_expr1
,date_or_time_expr2
The values to compare. Must be a date, a time, a timestamp, or an expression that can be evaluated to a date, a time, or a timestamp. The value
date_or_time_expr1
is subtracted fromdate_or_time_expr2
.
For minus sign:
date_expr1
,date_expr2
The values to compare. Must be a date, or an expression that can be evaluated to a date. The value
date_expr1
is subtracted fromdate_expr2
.
Returns¶
For DATEDIFF:
Returns an integer representing the difference in the number of units (seconds, days, and so on) between date_or_time_expr2
and
date_or_time_expr1
.
Returns NULL if any argument is NULL.
For minus sign:
Returns an integer representing the number of days difference between date_expr2
and
date_expr1
. (The units are always days.)
Returns an error if date_expr2
or date_expr1
is NULL.
Usage notes¶
For both DATEDIFF and minus sign:
Output values can be negative, for example, -12 days.
For DATEDIFF:
The function supports units of years, quarters, months, weeks, days, hours, minutes, seconds, milliseconds, microseconds, and nanoseconds.
If
date_or_time_part
isweek
(or any of its variations), the output is controlled by the WEEK_START session parameter. For more details, including examples, see Calendar weeks and weekdays.The unit (for example,
month
) used to calculate the difference determines which parts of the DATE, TIME, or TIMESTAMP field are evaluated. So, the unit determines the precision of the result.Smaller units are not used, so values are not rounded. For example, even though the difference between January 1, 2021 and February 28, 2021 is closer to two months than to one month, the following returns one month:
DATEDIFF(month, '2021-01-01'::DATE, '2021-02-28'::DATE)
For a DATE value:
year
uses only the year and disregards all the other parts.month
uses the month and year.day
uses the entire date.
For a TIME value:
hour
uses only the hour and disregards all the other parts.minute
uses the hour and minute.second
uses the hour, minute, and second, but not the fractional seconds.millisecond
uses the hour, minute, second, and first three digits of the fractional seconds. Fractional seconds are not rounded. For example,DATEDIFF(milliseconds, '2024-02-20 21:18:41.0000', '2024-02-20 21:18:42.1239')
returns 1.123 seconds, not 1.124 seconds.microsecond
uses the hour, minute, second, and first six digits of the fractional seconds. Fractional seconds are not rounded.nanosecond
uses the hour, minute, second, and all nine digits of the fractional seconds.
For a TIMESTAMP value:
The rules match the rules for DATE and TIME data types above. Only the specified unit and larger units are used.
For minus sign:
date_expr1
anddate_expr2
must both be dates. Times and timestamps are not allowed.
Examples¶
Calculate the difference in years between two timestamps:
SELECT DATEDIFF(year,
'2020-04-09 14:39:20'::TIMESTAMP,
'2023-05-08 23:39:20'::TIMESTAMP)
AS diff_years;
+------------+
| DIFF_YEARS |
|------------|
| 3 |
+------------+
Calculate the difference in hours between two timestamps:
SELECT DATEDIFF(hour,
'2023-05-08T23:39:20.123-07:00'::TIMESTAMP,
DATEADD(year, 2, ('2023-05-08T23:39:20.123-07:00')::TIMESTAMP))
AS diff_hours;
+------------+
| DIFF_HOURS |
|------------|
| 17544 |
+------------+
Demonstrate how date parts affect DATEDIFF calculations; also, demonstrate use of the minus sign for date subtraction:
SELECT column1 date_1, column2 date_2,
DATEDIFF(year, column1, column2) diff_years,
DATEDIFF(month, column1, column2) diff_months,
DATEDIFF(day, column1, column2) diff_days,
column2::DATE - column1::DATE AS diff_days_via_minus
FROM VALUES
('2015-12-30', '2015-12-31'),
('2015-12-31', '2016-01-01'),
('2016-01-01', '2017-12-31'),
('2016-08-23', '2016-09-07');
+------------+------------+------------+-------------+-----------+---------------------+
| DATE_1 | DATE_2 | DIFF_YEARS | DIFF_MONTHS | DIFF_DAYS | DIFF_DAYS_VIA_MINUS |
|------------+------------+------------+-------------+-----------+---------------------|
| 2015-12-30 | 2015-12-31 | 0 | 0 | 1 | 1 |
| 2015-12-31 | 2016-01-01 | 1 | 1 | 1 | 1 |
| 2016-01-01 | 2017-12-31 | 1 | 23 | 730 | 730 |
| 2016-08-23 | 2016-09-07 | 0 | 1 | 15 | 15 |
+------------+------------+------------+-------------+-----------+---------------------+
Demonstrate how time parts affect DATEDIFF calculations:
ALTER SESSION SET TIMESTAMP_NTZ_OUTPUT_FORMAT = 'DY, DD MON YYYY HH24:MI:SS';
SELECT column1 timestamp_1, column2 timestamp_2,
DATEDIFF(hour, column1, column2) diff_hours,
DATEDIFF(minute, column1, column2) diff_minutes,
DATEDIFF(second, column1, column2) diff_seconds
FROM VALUES
('2016-01-01 01:59:59'::TIMESTAMP, '2016-01-01 02:00:00'::TIMESTAMP),
('2016-01-01 01:00:00'::TIMESTAMP, '2016-01-01 01:59:00'::TIMESTAMP),
('2016-01-01 01:00:59'::TIMESTAMP, '2016-01-01 02:00:00'::TIMESTAMP);
+---------------------------+---------------------------+------------+--------------+--------------+
| TIMESTAMP_1 | TIMESTAMP_2 | DIFF_HOURS | DIFF_MINUTES | DIFF_SECONDS |
|---------------------------+---------------------------+------------+--------------+--------------|
| Fri, 01 Jan 2016 01:59:59 | Fri, 01 Jan 2016 02:00:00 | 1 | 1 | 1 |
| Fri, 01 Jan 2016 01:00:00 | Fri, 01 Jan 2016 01:59:00 | 0 | 59 | 3540 |
| Fri, 01 Jan 2016 01:00:59 | Fri, 01 Jan 2016 02:00:00 | 1 | 60 | 3541 |
+---------------------------+---------------------------+------------+--------------+--------------+
Use the CURRENT_TIMESTAMP function with the DATEDIFF function to calculate the difference in years, months, and days between a specified timestamp and the current timestamp:
SELECT column1 specified_timestamp,
column2 timestamp_now,
DATEDIFF(year, column1, column2) diff_years,
DATEDIFF(month, column1, column2) diff_months,
DATEDIFF(day, column1, column2) diff_days,
column2::DATE - column1::DATE AS diff_days_via_minus
FROM VALUES
('2012-08-23 09:00:00.000 -0700', CURRENT_TIMESTAMP);
+-------------------------------+-------------------------------+------------+-------------+-----------+---------------------+
| SPECIFIED_TIMESTAMP | TIMESTAMP_NOW | DIFF_YEARS | DIFF_MONTHS | DIFF_DAYS | DIFF_DAYS_VIA_MINUS |
|-------------------------------+-------------------------------+------------+-------------+-----------+---------------------|
| 2012-08-23 09:00:00.000 -0700 | 2024-09-04 17:21:12.189 -0700 | 12 | 145 | 4395 | 4395 |
+-------------------------------+-------------------------------+------------+-------------+-----------+---------------------+