String & Binary Functions (Matching/Comparison)
Allows case-insensitive matching of strings based on comparison with one or more patterns.
The operation is similar to
LIKE. If the input string matches any of the patterns, this returns the input string.
<subject> ILIKE ANY (<pattern1> [, <pattern2> ... ] ) [ ESCAPE <escape_char> ]
The string to compare to the pattern(s).
The pattern(s) that the string is to be compared to. You must specify at least one pattern.
Character(s) inserted in front of a wildcard character to indicate that the wildcard should be interpreted as a regular character rather than as a wildcard.
The data type of the returned value is VARCHAR.
SQL wildcards are supported in
An underscore (
_) matches any single character.
A percent sign (
%) matches any sequence of zero or more characters.
patterninclude newline characters (
The pattern is considered a match if the pattern matches the entire input string (subject). To match a sequence anywhere within a string, start and end the pattern with
%, for example ‘%something%’.
NULL does not match NULL. In other words, if the subject is NULL and one of the patterns is NULL, that is not considered a match.
If the function is used with a subquery, the subquery should return a single row.
For example, the following should be used only if the subquery returns a single row:
SELECT ... WHERE x LIKE ANY (SELECT ...)
This shows how to use ILIKE ANY:
Create a table that contains some strings:CREATE OR REPLACE TABLE ilike_example(subject varchar(20)); INSERT INTO ilike_example VALUES ('jane doe'), ('Jane Doe'), ('JANE DOE'), ('John Doe'), ('John Smith');SELECT * FROM ilike_example WHERE subject ILIKE ANY ('jane%', '%SMITH') ORDER BY subject; +------------+ | SUBJECT | |------------| | JANE DOE | | Jane Doe | | John Smith | | jane doe | +------------+
For examples of how to use wildcard characters, see the documentation of the related function LIKE ANY.